The pair of Indian stars Sania Mirza and Rohan Bopanna, who played the last Grand Slam, has entered the quarterfinals of the mixed category of the Australian Open. The Indian pair defeated Uruguayan pair of Ariel Behar and Makoto Ninomiya 6-4 7-6.

The Indians dominated the first set of the match which lasted one hour and 17 minutes. After that, the Uruguayan-Japanese pair put up an amazing fight, although the pair could not take the match till the last set.

On Tuesday, the Indian pair will face the Latvian pair of Jelena Ostapenko and David Vega Hernandez of Spain.

Bopanna-Mirza had won the French Open mixed doubles title six years back in 2017. Talking about the first Grand Slam of the year, Mirza became the champion in 2009 with Mahesh Bhupathi at the Australian Open.

Match report now.

Mirza-Bopanna won the first set easily
The Indian pair easily won the first set of this Round of 16 encounter. Its score was 6-4. In the second set, the Uruguayan-Japanese pair put up a tough fight for Mirza-Bopanna. The match went to the tie-breaker, however, the victory went in favor of the Indians. Its score was 7(11)-6(9).

beat Fourlis-Saville
The Indian pair, semi-finalists at the Rio Olympics, had defeated Australian wild card pair Jamie Fourlis and Luke Saville 7-5, 6-3 in one hour and 14 minutes two days ago.

Mirza lost in women’s doubles in 2 hours
On Day 7 of the first Grand Slam of the year, Indian star Sania Mirza, along with her partner Ana Danilina, were upset in the second round. The Indo-Kazakh 8th seed pair went down 4-6, 6-4, 2-6 to the unseeded pair of Belgium’s Alison Van Uitvank and Ukraine’s Anhelina Kalinina. This fight lasted for about 2 hours.

Sania Mirza and Ana Danilina had entered the women’s doubles second round after defeating the Hungarian-American pair of Dalma Gulfi and Bernarda Pera.